Cerinta completa
We define subsequence as any subset of an array. We define a subarray as a contiguous subsequence in an array.
Given an array, find the maximum possible sum among:
- all nonempty subarrays.
- all nonempty subsequences.
Print the two values as space-separated integers on one line.
Note that empty subarrays/subsequences should not be considered.
Example
The maximum subarray sum is comprised of elements at inidices . Their sum is . The maximum subsequence sum is comprised of elements at indices and their sum is .
Function Description
Complete the maxSubarray function in the editor below.
maxSubarray has the following parameter(s):
- int arr[n]: an array of integers
Returns
- int[2]: the maximum subarray and subsequence sums
Input Format
The first line of input contains a single integer , the number of test cases.
The first line of each test case contains a single integer .
The second line contains space-separated integers where .
Constraints
The subarray and subsequences you consider should have at least one element.
Sample Input 0
2
4
1 2 3 4
6
2 -1 2 3 4 -5
Sample Output 0
10 10
10 11
Explanation 0
In the first case: The maximum sum for both types of subsequences is just the sum of all the elements since they are all positive.
In the second case: The subarray is the subarray with the maximum sum, and is the subsequence with the maximum sum.
Sample Input 1
1
5
-2 -3 -1 -4 -6
Sample Output 1
-1 -1
Explanation 1
Since all of the numbers are negative, both the maximum subarray and maximum subsequence sums are made up of one element, .
Limbajul de programare folosit: cpp14
Cod:
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int maxSubArray(int arr[], int n) {
int maxSoFar = INT8_MIN;
int maxEnding = INT8_MIN;
for (int i = 0; i < n; i++) {
maxEnding = max(maxEnding + arr[i], arr[i]);
maxSoFar = max(maxSoFar, maxEnding);
}
return maxSoFar;
}
int maxSubsequence(int arr[], int n) {
int maxSoFar = INT8_MIN;
int sum = 0;
for (int i = 0; i < n; i++) {
maxSoFar = max(maxSoFar, arr[i]);
if (arr[i] > 0) {
sum += arr[i];
}
}
if (sum == 0) { return maxSoFar; }
return sum;
}
int main() {
int T;
cin >> T;
for (int t = 0; t < T; t++) {
int n;
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) { cin >> arr[i]; }
cout << maxSubArray(arr, n);
cout << " " << maxSubsequence(arr, n);
cout << "\n";
}
return 0;
}
Scor obtinut: 1.0
Submission ID: 464604751
Link challenge: https://www.hackerrank.com/challenges/maxsubarray/problem
