Cerinta completa
A bracket is considered to be any one of the following characters: (, ), {, }, [, or ].
Two brackets are considered to be a matched pair if the an opening bracket (i.e., (, [, or {) occurs to the left of a closing bracket (i.e., ), ], or }) of the exact same type. There are three types of matched pairs of brackets: [], {}, and ().
A matching pair of brackets is not balanced if the set of brackets it encloses are not matched. For example, {[(])} is not balanced because the contents in between { and } are not balanced. The pair of square brackets encloses a single, unbalanced opening bracket, (, and the pair of parentheses encloses a single, unbalanced closing square bracket, ].
By this logic, we say a sequence of brackets is balanced if the following conditions are met:
- It contains no unmatched brackets.
- The subset of brackets enclosed within the confines of a matched pair of brackets is also a matched pair of brackets.
Given strings of brackets, determine whether each sequence of brackets is balanced. If a string is balanced, return YES. Otherwise, return NO.
Function Description
Complete the function isBalanced in the editor below.
isBalanced has the following parameter(s):
- string s: a string of brackets
Returns
- string: either
YESorNO
Input Format
The first line contains a single integer , the number of strings.
Each of the next lines contains a single string , a sequence of brackets.
Constraints
- , where is the length of the sequence.
- All chracters in the sequences ∈ { {, }, (, ), [, ] }.
Output Format
For each string, return YES or NO.
Sample Input
STDIN Function
----- --------
3 n = 3
{[()]} first s = '{[()]}'
{[(])} second s = '{[(])}'
{{[[(())]]}} third s ='{{[[(())]]}}'
Sample Output
YES
NO
YES
Explanation
- The string
{[()]}meets both criteria for being a balanced string. - The string
{[(])}is not balanced because the brackets enclosed by the matched pair{and}are not balanced:[(]). - The string
{{[[(())]]}}meets both criteria for being a balanced string.
Limbajul de programare folosit: cpp14
Cod:
#include <bits/stdc++.h>
using namespace std;
string isBalanced(string s) {
stack<char> st;
for (auto c: s) {
switch (c) {
case '{':
case '(':
case '[':
st.push(c);
break;
case '}':
if (st.empty() || (st.top() != '{')) {
return "NO";
}
st.pop();
break;
case ')':
if (st.empty() || (st.top() != '(')) {
return "NO";
}
st.pop();
break;
case ']':
if (st.empty() || (st.top() != '[')) {
return "NO";
}
st.pop();
break;
}
}
return st.empty() ? "YES" : "NO";
}
int main(){
int t;
cin >> t;
for(int a0 = 0; a0 < t; a0++){
string s;
cin >> s;
cout << isBalanced(s) << endl;
}
return 0;
}
Scor obtinut: 1.0
Submission ID: 464653102
Link challenge: https://www.hackerrank.com/challenges/balanced-brackets/problem
